if sin p = 3/5 and p is an acute angle, what is the value of tan p.
trigonometry
Given that tan x = 5/12, what is the value of sin x + cos x?
draw a triangle with opposite leg=3 and hypotenuse=5
tan p = opposite/adjacent = 3/4
similarly, in a 5-12-13 right triangle
sinx + cosx = 5/13 + 12/13
timilehin oyewole
my name I'd Oyewole timilehin
The answer is 4
I can't find
Tank=8/12
5-12-13
=5/13+12/13
To find the value of tan p, we can use the relationship between sine, cosine, and tangent in a right triangle. Let's start by drawing a right triangle.
Step 1: Draw a right triangle.
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| \
p | \
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|____\
x
In our triangle, the angle p is an acute angle, so it is one of the non-right angles. The side opposite to angle p is represented as "x."
Step 2: Label the sides of the triangle.
We are given that sin p = 3/5, which tells us that the ratio of the side opposite angle p to the hypotenuse is 3/5.
We can use Pythagoras' theorem to find the remaining side. Since we have the opposite side ("x") and the hypotenuse, we can find the adjacent side.
Step 3: Use Pythagoras' theorem to find the length of the adjacent side.
According to Pythagoras' theorem:
(Adjacent Side)^2 = (Hypotenuse)^2 - (Opposite Side)^2
Let's substitute the known values into the equation:
(Adjacent Side)^2 = (5)^2 - (3)^2
(Adjacent Side)^2 = 25 - 9
(Adjacent Side)^2 = 16
Adjacent Side = 4
Now we have the lengths of both the opposite side (3) and the adjacent side (4).
Step 4: Find the value of tan p.
Tan p is equal to the ratio of the opposite side to the adjacent side in a right triangle.
Tan p = Opposite Side/Adjacent Side
Tan p = 3/4
Therefore, the value of tan p is 3/4.