Which value of k will make the lines parallel r= (1,2)+s(2,3), S e R
and 12x + ky= 0?
Ok so I used ratios and got k=8. Is that right?
Pls n thanks! :)
r has slope 3/2, so maybe not k=8, yeah?
I did this (used ratios)
3/2=12/k and got k=8
yes, but 12x+8y=0 has slope -3/2
To determine the value of k that will make the lines parallel, you need to compare the slopes of the two lines. If the slopes are equal, then the lines are parallel.
The first line is given by r = (1,2) + s(2,3). This can be rewritten as x = 1 + 2s and y = 2 + 3s. The slope of this line is equal to the coefficient of s in the y-coordinate, which is 3.
The second line is given by 12x + ky = 0. We can rewrite this equation to isolate y: y = (-12/k)x. The slope of this line is equal to the coefficient of x, which is -12/k.
To make the two lines parallel, the slopes must be equal: 3 = -12/k.
To solve for k, we can cross-multiply and solve the resulting equation:
3k = -12
k = -12/3
k = -4
Therefore, the correct value of k that will make the lines parallel is k = -4, not k = 8 as you mentioned.
So your answer is incorrect; the correct value of k is -4, not 8.