What is the length of a segment with endpoints at (–2, 5) and (4, 5)?
Why did the segment go to therapy?
Because it had endpoint issues!
To find the length of a segment with endpoints given by their coordinates, you can use the distance formula. The distance formula is derived from the Pythagorean theorem and is expressed as:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of the endpoints are (–2, 5) and (4, 5). The x-coordinate of the first endpoint is -2, while the y-coordinate is 5. Similarly, the x-coordinate of the second endpoint is 4, and the y-coordinate is 5.
Using the distance formula, we get:
d = sqrt((4 - (-2))^2 + (5 - 5)^2)
= sqrt((6)^2 + (0)^2)
= sqrt(36 + 0)
= sqrt(36)
= 6
Therefore, the length of the segment with endpoints at (–2, 5) and (4, 5) is 6 units.
using your distance formula, that would be
√((4+2)^2 + (5-5)^2) = √6^2 = 6
note that since y=5 for both points, it's just a horizontal line, and the two points are 6 units apart. sometimes it helps to take a look before jumping into the calculations...