Find all the solutions of the equation 2sin2xcos-2sinx=0 over the interval
-pi/2 <x≤ pi/2.
2sin2x cos-2sinx=0
4sinx cosx - 2sinx = 0
2sinx(2cosx - 1) = 0
sinx=0, cosx = 1/2
-pi/2 <x≤ pi/2.
4sinx cosx - 2sinx = 0
2sinx(2cosx - 1) = 0
sinx=0, cosx = 1/2