How many grams of HCl can you make from 110.0 g H2S in the reaction
3 H2S + 2 FeCl3 ---> 6 HCl + Fe2S3
mols H2S = g/molar mass = 110.0/molar mass H2S = about 3 but that's just a guess.
For every 3 mols H2S you get 6 mols HCl so mols HCl is about 6. Again an estimate.
Then grams HCl = mols HCl x molar mass HCl = ?
Well, this is a stinky situation! Let's break it down. According to the balanced equation, we have 3 moles of H2S forming 6 moles of HCl. To figure out the grams, we need to multiply the mole ratio by the molar mass.
The molar mass of H2S is approximately 34.08 g/mol, while the molar mass of HCl is around 36.46 g/mol.
First, we need to convert the mass of H2S (110.0 g) into moles. Using the molar mass, we have:
110.0 g H2S * (1 mol H2S/34.08 g H2S) = 3.2267 mol H2S
Next, we can use the mole ratio to determine the number of moles of HCl:
3.2267 mol H2S * (6 mol HCl/3 mol H2S) = 6.4534 mol HCl
Finally, we can convert the moles of HCl into grams:
6.4534 mol HCl * (36.46 g HCl/1 mol HCl) = 235.25 g HCl
So, you can make approximately 235.25 grams of HCl from 110.0 grams of H2S. Just be careful with the fumes, they're nothing to sneeze at!
To determine the number of grams of HCl that can be produced from 110.0 g of H2S, we need to use the stoichiometry of the reaction.
According to the balanced equation:
3 H2S + 2 FeCl3 ---> 6 HCl + Fe2S3
We can see that for every 3 moles of H2S reacted, 6 moles of HCl are produced.
Step 1: Convert grams of H2S to moles.
Molar mass of H2S = 2(1.008) + 32.06 = 34.08 g/mol
Moles of H2S = 110.0 g / 34.08 g/mol = 3.226 mol
Step 2: Determine the ratio of moles of H2S to moles of HCl.
Based on the balanced equation, the ratio is 3 moles H2S : 6 moles HCl.
Step 3: Convert moles of HCl to grams.
Molar mass of HCl = 1.007 + 35.45 = 36.46 g/mol
Grams of HCl = 6 moles HCl × 36.46 g/mol = 218.76 g
Therefore, you can make 218.76 grams of HCl from 110.0 grams of H2S in the given reaction.
To determine the number of grams of HCl produced from 110.0 g of H2S, we need to use stoichiometry and the balanced equation for the reaction.
Step 1: Write the balanced chemical equation:
3 H2S + 2 FeCl3 -> 6 HCl + Fe2S3
This equation shows that for every 3 moles of H2S reacted, 6 moles of HCl are produced.
Step 2: Calculate the molar mass of H2S and HCl:
H2S: 2(1.008 g/mol) + 32.06 g/mol = 34.076 g/mol
HCl: 1(1.008 g/mol) + 35.45 g/mol = 36.458 g/mol
Step 3: Convert the given mass of H2S to moles:
110.0 g H2S * (1 mol H2S / 34.076 g H2S) = 3.230 mol H2S
Step 4: Use the stoichiometry of the reaction to find the moles of HCl produced:
3.230 mol H2S * (6 mol HCl / 3 mol H2S) = 6.460 mol HCl
Step 5: Calculate the mass of HCl produced:
6.460 mol HCl * (36.458 g HCl / 1 mol HCl) = 235.778 g HCl
So, from 110.0 g of H2S, you can make approximately 235.778 grams of HCl.