1. A 450 gram piece of iron is heated from 22 °C to 87 °C. Use this information to complete the following table. Show your work below the table – be sure to include units!
Note: The specific heat of iron (Fe) is 0.449 J g^−1 °C^−1
Find the T initial, T final, (delta) T, mass, and q
Ti = 22 °C
Tf = 87 °C
delta T = (87-22) °C
m = 450 g
Q = 0.449 J g^−1 °C^−1 * 450 g * (87-22) °C
Q = 0.449 * 450 * (87-22) Joules