When magnesium metal (Mg) is burned, it forms MgO. How many moles of oxygen gas (O2) are needed to burn 20 moles of Mg? The balanced equation is:
2Mg + O2 --> 2MgO
First let me caution you that when Mg is BURNED IN OXYGEN the product is MgO. Burn it in N2) and the product will be Mg3N2.
2Mg + O2 --> 2MgO
If you have 20 mols Mg, you will need 20 mols Mg x (1 mol O2/2 mols Mg) = 20*1/2 = 10 mols O2.
When is the produced when mg is burned by oxtgen???
Well, it looks like you have a burning desire to figure this out! Let's do some mole math, shall we?
According to the balanced equation, we need 1 mole of O2 for every 2 moles of Mg. So, if we have 20 moles of Mg, we can say that we need half as many moles of O2.
Dividing 20 moles by 2 gives us 10 moles of O2. So, you would need 10 moles of O2 to burn 20 moles of Mg.
But hey, remember, in real life, it's all about being safe rather than setting the world on fire!
To determine how many moles of oxygen gas (O2) are needed to burn 20 moles of magnesium (Mg), we can use the balanced equation:
2Mg + O2 -> 2MgO
From the equation, we can see that the ratio between magnesium (Mg) and oxygen gas (O2) is 2:1. This means that for every 2 moles of magnesium, we need 1 mole of oxygen gas.
Therefore, to find the number of moles of oxygen gas required to burn 20 moles of magnesium, we can use the ratio mentioned above.
(20 moles of Mg) x (1 mole of O2 / 2 moles of Mg) = 10 moles of O2
Therefore, 10 moles of oxygen gas (O2) are needed to burn 20 moles of magnesium (Mg).
To determine the number of moles of oxygen gas (O2) needed to burn 20 moles of magnesium (Mg), we can use the balanced equation:
2Mg + O2 --> 2MgO
The equation tells us that 2 moles of magnesium react with 1 mole of oxygen gas to produce 2 moles of magnesium oxide.
By looking at the balanced equation, we can conclude that the ratio of moles of magnesium to moles of oxygen is 2:1. This means that for every 2 moles of magnesium, we need 1 mole of oxygen gas.
Since we have 20 moles of magnesium, we can set up a proportion to find the number of moles of oxygen gas needed:
2 moles Mg / 1 mole O2 = 20 moles Mg / x moles O2
Simplifying this equation, we have:
2 / 1 = 20 / x
Cross-multiplying, we get:
2x = 20
Dividing both sides by 2, we find:
x = 10
Therefore, 10 moles of oxygen gas (O2) are needed to burn 20 moles of magnesium (Mg).