Calculate the volume in ml of:
a. 12.5 g of calcium carbonate from a 0.12 M solution
b. 0.850 moles of sodium nitrate from a 0.500 M solution
[12.5g of CaCO3*(1 mole/100.09g)/(0.12M)]*(10^3mL/L)=????? <==== two significant figures.
(0.850 moles/0.500M)*(10^3mL/L)=???? <===== three significant figures
To calculate the volume in mL of a substance from a given mass or number of moles and concentration of a solution, we can use the equation:
Volume (in mL) = (Mass or moles / Concentration) * 1000
Now, let's calculate the volumes for each given scenario:
a. 12.5 g of calcium carbonate from a 0.12 M solution:
Step 1: Convert the mass from grams to moles.
We need to know the molar mass of calcium carbonate (CaCO3). It is:
Ca: 40.08 g/mol
C: 12.01 g/mol
O: 16.00 g/mol x 3 = 48.00 g/mol
Total molar mass of CaCO3 = 40.08 + 12.01 + 48.00 = 100.09 g/mol
Now, calculate the number of moles of calcium carbonate:
Number of moles = Mass / Molar mass = 12.5 g / 100.09 g/mol ≈ 0.1249 moles
Step 2: Calculate the volume using the formula:
Volume (in mL) = (Mass or moles / Concentration) * 1000
Volume = (0.1249 moles / 0.12 M) * 1000 = 1041.67 mL ≈ 1042 mL
Therefore, the volume of 12.5 g of calcium carbonate from a 0.12 M solution is approximately 1042 mL.
b. 0.850 moles of sodium nitrate from a 0.500 M solution:
Using the same formula as before:
Volume (in mL) = (Mass or moles / Concentration) * 1000
Step 1: Calculate the volume:
Volume = (0.850 moles / 0.500 M) * 1000 = 1700 mL
Therefore, the volume of 0.850 moles of sodium nitrate from a 0.500 M solution is 1700 mL.