If 32 g of kerosene of density 0.80 g/cm^3 are mixed with 8 g of water. What is the density of the resulting mixture
volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
How did you got the 48
I don't know how he got 48
Please 🙏 solve this question
volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
Is that the final answer
I don't really understand all this signs as it is written in this google so please make it easy for the audience GOD BLESS YOU
How did you get 48 as the answer
Answer
To find the density of the resulting mixture, we need to calculate the total mass and total volume of the mixture first.
The mass of the kerosene is given as 32 g. The mass of water is given as 8 g.
To calculate the total mass of the mixture, we add the mass of the kerosene and the mass of the water:
Total mass = mass of kerosene + mass of water
Total mass = 32 g + 8 g
Total mass = 40 g
Next, we need to calculate the total volume of the mixture. To do this, we need to know the volume of both the kerosene and water. Since the density of the kerosene is given as 0.80 g/cm^3, we can use this information to calculate its volume:
Volume of kerosene = mass of kerosene / density of kerosene
Volume of kerosene = 32 g / 0.80 g/cm^3
Volume of kerosene = 40 cm^3
Since the mass of water is given as 8 g and the density of water is 1 g/cm^3, we can directly say that the volume of water is 8 cm^3.
To calculate the total volume of the mixture, we add the volume of the kerosene and the volume of the water:
Total volume = volume of kerosene + volume of water
Total volume = 40 cm^3 + 8 cm^3
Total volume = 48 cm^3
Finally, the density of the resulting mixture is calculated by dividing the total mass by the total volume:
Density of mixture = Total mass / Total volume
Density of mixture = 40 g / 48 cm^3
Density of mixture = 0.833 g/cm^3
Therefore, the density of the resulting mixture is approximately 0.833 g/cm^3.