A particle with a charge of 0.08 C is moving at right angles to a uniform magnetic field with a strength of 0.8 T. The velocity of the charge is 800 m/s.
What is the magnitude of the magnetic force exerted on the particle?
Answer is in N
F = Q ( v cross B)
cross is the cross product in general v B sin theta
where theta is the angle between v and B
since here it is 90 degrees, sin theta = 1
and it is just
F =Q v B = .08 * 800 * 0.8 Newtons
To find the magnitude of the magnetic force exerted on the particle, we can use the formula for the magnetic force:
F = q * v * B * sin(theta)
Where:
F is the magnetic force
q is the charge of the particle
v is the velocity of the particle
B is the magnetic field strength
theta is the angle between the velocity vector and the magnetic field
Given:
q = 0.08 C
v = 800 m/s
B = 0.8 T
The particle is moving at right angles to the magnetic field, so the angle theta is 90 degrees.
Plugging in the values, we get:
F = 0.08 C * 800 m/s * 0.8 T * sin(90°)
Since sin(90°) = 1, the equation simplifies to:
F = 0.08 C * 800 m/s * 0.8 T * 1
Simplifying further, we get:
F = 51.2 N
Therefore, the magnitude of the magnetic force exerted on the particle is 51.2 N.
To find the magnitude of the magnetic force exerted on the particle, you can use the formula:
F = q * v * B * sin(theta)
Where:
F is the magnitude of the magnetic force
q is the charge of the particle
v is the velocity of the particle
B is the strength of the magnetic field
theta is the angle between the velocity vector and the magnetic field vector
In this case, the charge of the particle (q) is 0.08 C, the velocity (v) is 800 m/s, and the strength of the magnetic field (B) is 0.8 T.
Since the particle is moving at right angles to the magnetic field, the angle theta between the velocity vector and the magnetic field vector is 90 degrees.
Now, let's substitute these values into the formula:
F = (0.08 C) * (800 m/s) * (0.8 T) * sin(90°)
sin(90°) = 1, so the formula simplifies to:
F = (0.08 C) * (800 m/s) * (0.8 T) * 1
F = 0.064 N
Therefore, the magnitude of the magnetic force exerted on the particle is 0.064 N.