find the first five terms for the following arithmetic sequence tn =-5n-6
tn =-5n-6
t1 = -5(1) - 6 = -11
t2 = -5(2) - 6 = -16
...
tѼ = -5(Ѽ) - 6
..
t5 = .....
To find the first five terms of the arithmetic sequence, we need to substitute the values of n from 1 to 5 into the formula tn = -5n - 6.
Let's calculate the first five terms one by one:
For n = 1:
t1 = -5(1) - 6
t1 = -5 - 6
t1 = -11
So, the first term (t1) is -11.
For n = 2:
t2 = -5(2) - 6
t2 = -10 - 6
t2 = -16
So, the second term (t2) is -16.
For n = 3:
t3 = -5(3) - 6
t3 = -15 - 6
t3 = -21
So, the third term (t3) is -21.
For n = 4:
t4 = -5(4) - 6
t4 = -20 - 6
t4 = -26
So, the fourth term (t4) is -26.
For n = 5:
t5 = -5(5) - 6
t5 = -25 - 6
t5 = -31
So, the fifth term (t5) is -31.
Therefore, the first five terms of the arithmetic sequence are: -11, -16, -21, -26, -31.