Find the probability of drawing a 10 and a 3 in either order.
I could guess at an answer to your incomplete question, but
there is a high probability I would be wrong.
To find the probability of drawing a 10 and a 3 in either order, we first need to determine the total number of possible outcomes.
In a standard deck of 52 playing cards, there are 4 suits (hearts, diamonds, clubs, and spades) with 13 cards each (Ace through King).
The probability of drawing a 10 and a 3 in either order can be calculated by the following steps:
Step 1: Find the probability of drawing a 10.
- There are 4 different 10 cards in the deck (10 of hearts, 10 of diamonds, 10 of clubs, and 10 of spades).
- Therefore, the probability of drawing a 10 is 4/52 or 1/13.
Step 2: Find the probability of drawing a 3.
- Similarly, there are 4 different 3 cards in the deck (3 of hearts, 3 of diamonds, 3 of clubs, and 3 of spades).
- So, the probability of drawing a 3 is also 4/52 or 1/13.
Step 3: Multiply the probabilities from steps 1 and 2 to find the probability of getting both a 10 and a 3.
- Multiplying 1/13 by 1/13 gives us (1/13) x (1/13) = 1/169.
Step 4: Since the order of the cards can be 10-3 or 3-10, we need to double the probability calculated in step 3.
- Multiplying 1/169 by 2 gives us 2/169.
Therefore, the probability of drawing a 10 and a 3 in either order is 2/169.
To find the probability of drawing a 10 and a 3 in either order, we first need to determine the total number of possible outcomes.
Let's assume that we are drawing two cards randomly from a standard deck of 52 playing cards. There are a total of 52 cards in the deck, so the first card can be any of the 52 cards. After drawing the first card, there are 51 remaining cards in the deck.
Now, we'll calculate the number of favorable outcomes, which is the number of ways to draw a 10 and a 3 in either order.
Option 1: Drawing a 10 first and then a 3.
There are four 10s in the deck (one for each suit), and after drawing a 10, there are three remaining 3s in the deck. So, the probability of drawing a 10 first and then a 3 is (4/52) * (3/51).
Option 2: Drawing a 3 first and then a 10.
Similarly, there are four 3s in the deck, and after drawing a 3, there are four remaining 10s in the deck. So, the probability of drawing a 3 first and then a 10 is (4/52) * (4/51).
To find the total probability, we need to sum the probabilities of both options:
P(drawing a 10 and a 3 in either order) = (4/52) * (3/51) + (4/52) * (4/51)
Calculating this expression, we get:
P(drawing a 10 and a 3 in either order) ≈ 0.023
Therefore, the probability of drawing a 10 and a 3 in either order is approximately 0.023 or 2.3%.