Calculate the molarity of trioxonitrate (v) acid containing 6.0g of acid in 250cm
To calculate the molarity of a solution, we need to know the moles of solute and the volume of the solution in liters.
First, we need to convert the mass of the trioxonitrate (V) acid from grams to moles. The molar mass of trioxonitrate (V) acid is 63 g/mol.
Mass of trioxonitrate (V) acid = 6.0 g
Molar mass of trioxonitrate (V) acid = 63 g/mol
Number of moles = Mass / Molar mass
Number of moles = 6.0 g / 63 g/mol
Now, we need to convert the volume of the solution from cm^3 to liters. There are 1000 cm^3 in 1 liter.
Volume of solution = 250 cm^3
Volume of solution in liters = 250 cm^3 / 1000 cm^3/L
Finally, we can calculate the molarity using the formula:
Molarity (M) = Number of moles / Volume of solution (in liters)
Substituting the values we calculated:
Molarity (M) = (6.0 g / 63 g/mol) / (250 cm^3 / 1000 cm^3/L)
Calculate the numerator first:
Molarity (M) = 0.09524 mol / (250 cm^3 / 1000 cm^3/L)
Now, divide the numerator by the denominator:
Molarity (M) = 0.09524 mol / 0.25 L
Molarity (M) = 0.38 M
Therefore, the molarity of the trioxonitrate (V) acid solution is 0.38 M.
To calculate the molarity of a solution, you need to know the mass of the solute (in grams) and the volume of the solution it is dissolved in (in liters).
Given:
Mass of trioxonitrate (v) acid = 6.0 g
Volume of solution = 250 cm³
To obtain molarity, you need to follow these steps:
Step 1: Convert the volume from cm³ to liters.
Since 1 cm³ is equal to 1 x 10^-3 liters, divide the volume by 1000:
Volume of solution = 250 cm³ ÷ 1000 = 0.25 L
Step 2: Calculate the moles of trioxonitrate (v) acid.
To do this, you need to know the molar mass of trioxonitrate (v) acid. The formula of trioxonitrate (v) acid is HNO₃, consisting of one hydrogen atom (1.008 g/mol), one nitrogen atom (14.01 g/mol), and three oxygen atoms (3 x 16.00 = 48.00 g/mol).
Molar mass of HNO₃ = 1.008 + 14.01 + 48.00 = 63.018 g/mol
Now, use the formula:
Moles = mass (in grams) ÷ molar mass
Moles = 6.0 g ÷ 63.018 g/mol = 0.0952 mol
Step 3: Calculate molarity.
Molarity (M) = moles ÷ volume (in liters)
Molarity = 0.0952 mol ÷ 0.25 L = 0.3808 M (rounded to four decimal places)
Therefore, the molarity of the trioxonitrate (v) acid solution is approximately 0.3808 M.