A brass with an original length of 2m at a temperature of 15 degree celsius,what will be it's length at 50 degree celsius
To determine the length of the brass at a different temperature, we need to use the coefficient of linear expansion for brass. The coefficient of linear expansion is the rate at which a material expands or contracts when its temperature changes.
The coefficient of linear expansion for brass is typically given as 18 x 10^(-6) per degree Celsius. It means that for every degree Celsius increase in temperature, brass expands by 18 x 10^(-6) times its original length.
To calculate the change in length, we can use the formula:
ΔL = α * L0 * ΔT
where:
ΔL is the change in length
α is the coefficient of linear expansion
L0 is the original length
ΔT is the change in temperature
Let's calculate:
Original length, L0 = 2m
Change in temperature, ΔT = 50°C - 15°C = 35°C
Coefficient of linear expansion, α = 18 x 10^(-6) / °C
ΔL = (18 x 10^(-6) / °C) * (2m) * (35°C)
= 0.00126m
To find the final length, we need to add the change in length to the original length:
Final length = Original length + Change in length
= 2m + 0.00126m
= 2.00126m
Therefore, the length of the brass at a temperature of 50°C would be 2.00126 meters.