A 78.1-kg skydiver is experiencing 247 Newton of air resistance. Determine the magnitude of the acceleration (in m/s/s) of the skydiver.
gravitational force (weight) is ... m g
acceleration = force / mass = [(m * g) - 247] / 78.1
To determine the magnitude of the acceleration of the skydiver, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
The formula for Newton's second law can be written as:
F = m * a
Where:
F is the force acting on the object (air resistance in this case),
m is the mass of the object (78.1 kg in this case), and
a is the acceleration of the object (what we need to find).
Rearranging the formula, we can solve for acceleration:
a = F / m
Plugging in the given values, we have:
a = 247 N / 78.1 kg
Calculating the division, we find:
a ≈ 3.16 m/s²
Therefore, the magnitude of the acceleration of the skydiver is approximately 3.16 m/s².
To determine the magnitude of the acceleration experienced by the skydiver, we need to use Newton's second law of motion. The formula for Newton's second law is:
F = m * a
Where:
F = Net force acting on the object (in Newtons),
m = Mass of the object (in kilograms), and
a = Acceleration of the object (in meters per second squared).
In this case, the force acting on the skydiver is the air resistance, which is given as 247 Newtons. The mass of the skydiver is 78.1 kg. We need to rearrange the formula to solve for acceleration (a):
a = F / m
Plugging in the values:
a = 247 N / 78.1 kg
Evaluating this expression:
a ≈ 3.16 m/s²
Therefore, the magnitude of the acceleration experienced by the skydiver is approximately 3.16 m/s².