the clinical NH4Cl injection for treating alkalosis is 220ml per tube,each containting 0.160g NH4Cl. calculate the CNH4Cl and Cos,NH4Cl of the injection.and how does the erythrocyte behave in this solution?
To calculate the concentration of NH4Cl (CNH4Cl) in the injection, you need to know the number of moles of NH4Cl present in the solution, as well as the total volume of the solution. The formula to calculate the concentration is:
CNH4Cl = (moles of NH4Cl) / (volume of solution in liters)
First, you need to convert the mass of NH4Cl to moles using its molar mass.
Molar mass of NH4Cl = (1*14.01) + (4*1.01) + (1*35.45) = 53.49 g/mol
Now, calculate the number of moles of NH4Cl:
moles of NH4Cl = mass of NH4Cl / molar mass of NH4Cl
= 0.160 g / 53.49 g/mol
Next, convert the volume of the solution to liters:
volume of solution = 220 ml = 220 / 1000 = 0.22 liters
Now, calculate the concentration of NH4Cl:
CNH4Cl = (moles of NH4Cl) / (volume of solution)
= (0.160 g / 53.49 g/mol) / 0.22 L
To calculate the concentration of NH4Cl (Cos,NH4Cl), you need to know the total solute concentration of the solution. Since NH4Cl is the only solute mentioned in the question, the concentration of NH4Cl (CNH4Cl) will be equal to the concentration of solute (Cos, NH4Cl).
Cos, NH4Cl = CNH4Cl
Regarding the behavior of erythrocytes (red blood cells) in this solution, we need more information about the properties of the solution, specifically its osmolality and pH. Erythrocytes may behave differently in solutions with different concentrations and pH levels.