Which pair of bonded atoms has the largest
dipole moment?
1. C N
2. N N
3. C O
4. C C
5. C F
The answer would be 5. C F, because these two atoms have the largest difference in electronegativity.
Well, let me use my clown powers of deduction here! If we're talking about dipole moments, we're talking about unequal sharing of electrons. And guess what? Fluorine is like that person who hogs the TV remote - it really loves electrons! So, the answer is 5. C F - because the bond between carbon (C) and fluorine (F) creates the largest dipole moment. Those two atoms just can't seem to share the electrons equally.
To determine which pair of bonded atoms has the largest dipole moment, we need to consider the electronegativity difference between the atoms. The larger the electronegativity difference, the stronger the polarity of the bond, resulting in a larger dipole moment.
Here are the electronegativity values of the elements mentioned:
C (Carbon) = 2.55
N (Nitrogen) = 3.04
O (Oxygen) = 3.44
F (Fluorine) = 3.98
Now, let's calculate the electronegativity differences for each pair of bonded atoms:
1. C-N: 3.04 - 2.55 = 0.49
2. N-N: 3.04 - 3.04 = 0.00
3. C-O: 3.44 - 2.55 = 0.89
4. C-C: 2.55 - 2.55 = 0.00
5. C-F: 3.98 - 2.55 = 1.43
Based on the calculations, the pair of bonded atoms with the largest dipole moment is C-F (option 5) because it has the largest electronegativity difference of 1.43.
To determine which pair of bonded atoms has the largest dipole moment, we need to consider the difference in electronegativity between the two atoms. The electronegativity is a measure of an atom's ability to attract electrons towards itself in a chemical bond.
The greater the difference in electronegativity between two bonded atoms, the larger the dipole moment will be. So, we need to compare the electronegativity of the atoms in each pair.
1. C N: The electronegativity of carbon (C) is about 2.5, and the electronegativity of nitrogen (N) is about 3.0. The difference is 3.0 - 2.5 = 0.5.
2. N N: Since both atoms are nitrogen (N), the electronegativity difference is zero.
3. C O: The electronegativity of carbon (C) is 2.5, and the electronegativity of oxygen (O) is about 3.5. The difference is 3.5 - 2.5 = 1.0.
4. C C: Since both atoms are carbon (C), the electronegativity difference is zero.
5. C F: The electronegativity of carbon (C) is 2.5, and the electronegativity of fluorine (F) is about 4.0. The difference is 4.0 - 2.5 = 1.5.
Comparing the electronegativity differences, we find:
1. C N: 0.5
2. N N: 0
3. C O: 1.0
4. C C: 0
5. C F: 1.5
From these values, we can see that the pair of atoms with the largest electronegativity difference, and thus the largest dipole moment, is C-F (option 5).