Two buses leave a city at the same time,one going north and the other east.The north bound bus travels 10km/hr faster than the east bound one.If they are 250km apart after 5hours,What is the speed of each bus?(Explain your answer)
If the slower bus has speed x, then
(5x)^2 + (5(x+10))^2 = 250^2
solve for x
Or, factor out the 25 and you have
x^2 + (x+10)^2 = 50^2
Now think of your basic 3-4-5 right triangle