I have a .283M of Nitric acid in 5500 kg of water. How much of 68% Nitric acid do I need to add to make the nitric acid solution 0.3M?
Is this molarity (M) or molality (m). If M what is the density of the 0.283 M solution.
It is M, Im going to say with that much water lets call the density 1.02
To find out how much of the 68% Nitric acid solution you need to add, we can start by calculating the moles of Nitric acid currently present in the 0.283M Nitric acid solution and the moles of Nitric acid required to make the solution 0.3M.
First, let's find the moles of Nitric acid in the initial solution:
Molarity (M) = moles of solute / volume of solution (in liters)
0.283M = moles of Nitric acid / (0.283L + 5,500L)
Since the volume of water is given in kg, we need to convert it to liters. Assuming the density of water is 1 g/mL, 5,500 kg is equal to 5,500 L.
Therefore:
0.283M = moles of Nitric acid / 5,500.283L
Moles of Nitric acid = 0.283M x 5,500.283L
Now, let's calculate the moles of Nitric acid required to make a 0.3M solution:
Molarity (M) = moles of solute / volume of solution (in liters)
0.3M = moles of Nitric acid / (volume of solution + volume of 68% Nitric acid)
We have the volume of solution (5,500 L) and we need to find the volume of 68% Nitric acid required.
Assuming the density of the 68% Nitric acid is 1 g/mL, we can convert the volume to liters by dividing by 1,000:
Volume of 68% Nitric acid (L) = (mass of 68% Nitric acid / density of 68% Nitric acid) / 1000
To find the mass of 68% Nitric acid, we can use the equation:
mass of solute = mass of solution x percentage of solute / 100
Given that the mass of the solution is 5500 kg, we can calculate the mass of 68% Nitric acid:
mass of 68% Nitric acid = 5500 kg x 68 / 100
Once we have the mass of the 68% Nitric acid, we can substitute it into the equation to find the volume:
Volume of 68% Nitric acid (L) = (mass of 68% Nitric acid / density of 68% Nitric acid) / 1000
Finally, after calculating the volume of the 68% Nitric acid needed, you can add it to the existing solution to make a 0.3M Nitric acid solution.