If the exterior angles of a quadrilateral are y, (2y+5),(y+15)and(2y+10)degrees,find y
well, they must add up to 360°, so add 'em up and solve for y.
y + (2y+5) + (y+15) + (2y+10) = 1080.
Y =
1 yes
Solving the question please
to me
To find the value of y in this case, we need to use the property that the sum of the exterior angles of any polygon is always 360 degrees.
In a quadrilateral, the sum of the four exterior angles is equal to 360 degrees. So, we can set up an equation:
y + (2y + 5) + (y + 15) + (2y + 10) = 360
Simplifying the equation, we combine like terms:
6y + 30 = 360
Next, we can isolate the variable y by subtracting 30 from both sides:
6y = 360 - 30
6y = 330
Finally, we solve for y by dividing both sides by 6:
y = 330 / 6
y = 55
Therefore, the value of y is 55.