What volume of glycerine C3H8o3. Density 1.26g/ml, should be taken to obtain 2.50mol of glycerine
Assuming glycerol is 100%, then
mass of 1 L = 1.26 g/mL x 1000 mL = 1260 grams in a liter.
molar mass glycerin = 92
1260/92 = 13.7 mols/L
13.7 mols/L x #L = 2.50 mols.
Solve for #L.
To find the volume of glycerine needed to obtain a certain amount in moles, we can use the formula:
Volume = Number of Moles / Density
Given:
Number of Moles (n) = 2.50 mol
Density (d) = 1.26 g/ml
First, we need to convert the given density from grams per milliliter (g/ml) to grams per mole (g/mol). This can be done by calculating the molar mass of glycerine.
The molar mass of glycerine (C3H8O3) can be calculated as follows:
(3 x molar mass of Carbon) + (8 x molar mass of Hydrogen) + (3 x molar mass of Oxygen)
The molar masses of carbon (C), hydrogen (H), and oxygen (O) are approximately:
C = 12.01 g/mol
H = 1.008 g/mol
O = 16.00 g/mol
Molar mass of glycerine:
(3 x 12.01) + (8 x 1.008) + (3 x 16.00) = 92.10 g/mol
Now, to calculate the density in g/mol, we divide the given density (1.26 g/ml) by the molar mass of glycerine (92.10 g/mol):
Density (g/mol) = 1.26 g/ml / 92.10 g/mol
Density (g/mol) ≈ 0.0137 g/mol
Now that we have the density in grams per mole, we can substitute the values into the formula:
Volume (ml) = Number of Moles (mol) / Density (g/ml)
Volume (ml) = 2.50 mol / 0.0137 g/ml
Calculating this gives us the volume in milliliters.