What volume (inL) of 0.187 MKCI solution will completely react with 0.117 L of a 0.142 M Pb(NO 3 ) 2 solution according to the following balanced chemical equation: 2 KCl(aq)+Pb(NO 3 ) 2 (aq) PbCl 2 (s)+2 KNO 3 ( aq )
I cleaned up your messy equation AND I put in an arrow to show where the reactants and products are. Be careful in the future to get this right.
2KCl(aq) + Pb(NO3 )2 (aq) ==> PbCl2 (s) + 2KNO3 ( aq )
mols of Pb(NO3)2 given = M x L = 0.142 x 0.117 = ?
mols of KCl needed = 2 x mols Pb(NO3)2 = ?. That comes from the coefficients in the balanced equation.
Then M KCl = mols KCl/L KCl. You have mols and M, substitute nd solve for L.
Post your work if you get stuck.