I have absolutely no idea how to do it and my teacher teach hecking fast too...
Zinc reacts with hydrochloric acid and hydrogen gas.If 130g of zinc reacted completely, calculate the volume of gas formed.
my second try.
my third try.
What temperature? What pressure? I assume you want the volume at STP.
Step 1. Write and balance the equation.
Zn + 2HCl => ZnCl2 + H2
Step 2. Convert what you have (130 g Zn) to mols.
mols = grams/atomic mass = 130/65.4 = approx 2 but this is a close estimate. You should repeat ALL of these calculations.
Step 3. Using the coefficients in the balanced equation, convert mols of what you have (mols Zn) to mols of what you want (H2).
approx 2 mols Zn x (1 mol H2/1 mol Zn) = approx 2 mol H2 gas.
Step 4. Convert mols H2 gas to the unit you want (volume in L)
You know 1 mol of any gas at STP occupies 22.4 L so
approx 2 mols H2 x 22.4 L/mol = ? Liters.
To calculate the volume of gas formed when 130g of zinc reacts completely with hydrochloric acid, we need to apply the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a chemical reaction.
Here's the step-by-step process to solve this problem:
Step 1: Write the balanced chemical equation.
The given balanced chemical equation for the reaction between zinc and hydrochloric acid is:
Zn + 2HCl → ZnCl2 + H2
Step 2: Determine the molar mass of zinc.
The molar mass of zinc (Zn) is 65.38 g/mol. This means that in 65.38 grams of zinc, we have one mole of zinc atoms.
Step 3: Calculate the number of moles of zinc.
To convert grams to moles, we can divide the given mass of zinc (130g) by its molar mass:
Number of moles of zinc = Mass of zinc / Molar mass of zinc
Number of moles of zinc = 130g / 65.38 g/mol
Number of moles of zinc = 1.989 mol
Step 4: Use the stoichiometric ratio to determine the number of moles of hydrogen gas produced.
From the balanced chemical equation, we can see that for every 1 mole of zinc reacted, 1 mole of hydrogen gas is produced. Therefore,
Number of moles of hydrogen gas = Number of moles of zinc = 1.989 mol
Step 5: Convert moles of hydrogen gas to volume using the ideal gas law.
The ideal gas law equation is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.
Assuming the pressure (P) and temperature (T) are constant, we can rearrange the ideal gas law equation to solve for volume (V):
V = nRT / P
Since we are not given the pressure (P) and temperature (T), we will assume standard conditions (1 atm and 273 K) for this calculation.
Using the values:
V = (1.989 mol) x (0.0821 L·atm/mol·K) x (273 K) / 1 atm
V = 45.84 L (rounded to two decimal places)
Therefore, the volume of gas formed when 130g of zinc reacts completely is approximately 45.84 liters.