The local reader’s club has a set of 36 hardback books and a set of 30 paperbacks. Each set can be divided equally among the club members. What is the greatest possible number of club members?
A.5*
B.6
C.30
D.180
what are all of the answers
Would it be 6? I just re-did the math and I wanted to verify if it was right.
thanls
Yes, 6.
The local reader's club has a set of 36 hardback books and a set of 39 paperbacks. Each set can be divided equally among members. What is the greatest possible number of club members? * plz help me *
To find the greatest possible number of club members, we need to determine the highest common factor (HCF) of 36 and 30.
To do this, we can list the factors of each number:
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
From these lists, we can see that the common factors of 36 and 30 are 1, 2, 3, and 6.
The highest common factor of 36 and 30 is 6, which means that the sets of books can be divided equally among 6 club members.
Therefore, the correct answer is B. 6.