A 2meters crowbar is employed to lift a load 300kg. What force must be applied to one end of the crowbar when a stump acting as a fulcrum is placed under the crowbar 0.5meter away from the end on which the load rests? Neglect the weight of the crowbar.
the lifting force is applied 3 times as far from the fulcrum as the load
f = m * g / 3 = (300 kg * 9.81 m/s^2) / 3
F1 = applied force.
F2 = M*g = 300*9.8 = 2940 N. = force of the load.
F1*d1 = F2*d2.
F1*1.5 = 2940*0.5,
F1 = ___ Newtons.
To solve this problem, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the anticlockwise moments about the same point.
First, let's define the distances involved:
Distance from fulcrum to the end of the crowbar where the force is applied (F): 2 meters
Distance from fulcrum to the end of the crowbar where the load is placed (L): 0.5 meters
Now, let's calculate the moments involved:
Moment of the force applied (F) = Force (F) × Distance (F)
Moment of the load (L) = Load (L) × Distance (L)
According to the principle of moments, the clockwise moment (force side) must be equal to the anticlockwise moment (load side):
F × 2 = 300 × 0.5
Now, we can solve for the force (F):
F × 2 = 150
Divide both sides by 2:
F = 150 / 2 = 75 kg
Therefore, the force that must be applied to one end of the crowbar is 75 kg.