I have a question of velocity-time graph in which a girl throws ball from the top of cliff.The ball has mass of 250 g. How to calculate the magnitude of change in momentum of the ball between the time it leaves the girls hand to time t=4.0s.
v = -9.8t
p = mv
Now just plug in your numbers.
That is if she dropped the ball, not threw it :)
To calculate the magnitude of change in momentum of the ball between the time it leaves the girl's hand to time t=4.0s, we need to utilize the velocity-time graph.
First, we need to identify the relevant information from the velocity-time graph. The magnitude of change in momentum can be calculated by using the equation:
Change in momentum = Final momentum - Initial momentum
To find the initial momentum, we need to determine the velocity of the ball as it leaves the girl's hand at the top of the cliff. This can be done by finding the initial velocity from the graph.
For example, if the graph represents the velocity of the ball as a function of time, you can look at the vertical axis to find the value of the initial velocity. Let's assume that the graph shows the initial velocity as 10 m/s.
Next, we need to find the final momentum of the ball at time t=4.0s. To do this, we need to find the final velocity at time t=4.0s. Again, we can refer to the graph and find the value of the final velocity.
If, for instance, the graph shows that the final velocity at t=4.0s is 20 m/s, we can now calculate the magnitude of change in momentum as follows:
Change in momentum = Final momentum - Initial momentum
= (mass of the ball) x (final velocity) - (mass of the ball) x (initial velocity)
= (0.25 kg) x (20 m/s) - (0.25 kg) x (10 m/s)
= 5 kg⋅m/s
Therefore, the magnitude of change in momentum of the ball between the time it leaves the girl's hand to time t=4.0s is 5 kg⋅m/s.