kg mass moving with a speed of 30 of 30ms-1 is brought to rest in 2.5sec, calculate the magnitude of the constant retarding force
a = -30/2.5 = -12 m/s^2
and as usual,
F = ma
V = Vo + a*t.
0 = 30 + a*2.5,
a = - 12 m/s^2.
F = M*a = 8 * (-12) =
To calculate the magnitude of the constant retarding force, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration. In this case, the object is the kg mass, and we need to find the force.
To find the acceleration of the object, we can use the equation of motion:
v = u + at
Where:
v = final velocity = 0 m/s (since the object is brought to rest)
u = initial velocity = 30 m/s
t = time taken to come to rest = 2.5 s
Rearranging the equation, we have:
a = (v - u) / t
Plugging in the values, we get:
a = (0 - 30) / 2.5
a = -12 m/s^2
Since the object is brought to rest, the acceleration is negative because it is opposing the initial motion.
Now, we can substitute the mass (kg) and acceleration (m/s^2) into Newton's second law of motion:
F = m * a
Plugging in the values, we get:
F = 1 kg * (-12 m/s^2)
F = -12 N
The magnitude of the constant retarding force is 12 N, directed opposite to the initial motion of the object.