Why does my try/catch statement gives me an input mismatchexception error and kills the program?
try {
System.out.println("enter how many salaries");
amount = input.nextInt();
}catch(InputMismatchException e) {
System.out.println("enter a valid number for the amount of salaries");
amount = input.nextInt();
}
im using that to try to check that an int is entered into the sccanner instead of a number any idea why id still be getting an inputmismatchexception
In your code snippet, the `try-catch` block is used to catch an `InputMismatchException` when the user enters a value that cannot be converted to an integer. However, the code inside your `catch` block is still calling `input.nextInt()` again, which can cause the same error if the next input is not a valid integer.
To fix this issue, you can modify your code as follows:
```java
try {
System.out.println("Enter the number of salaries: ");
amount = input.nextInt();
} catch (InputMismatchException e) {
System.out.println("Enter a valid number for the amount of salaries: ");
input.nextLine(); // Consume the invalid input
amount = input.nextInt();
}
```
In this updated code, after catching the `InputMismatchException`, we call `input.nextLine()` to consume the invalid input and move to the next line. This helps to clear the contents of the scanner's buffer. Then, we call `input.nextInt()` again to read the valid integer input.
By including `input.nextLine()` in the `catch` block, we ensure that any invalid input is properly discarded, preventing the code from getting stuck in an infinite loop.
Remember to import the necessary package (`java.util.InputMismatchException`) at the top of your file for the code to compile correctly.