1000w heater is used in the determination of specific latent heat of vaporization of water and it took 4 minutes for 500g of water to be changed to steam. Calculate the latent heat of vaporization of water.
4 min * 60 = 240 seconds
1000 W = 1000 Joule / second
so we put 240,000 Joules into 0.5 kg of the water
so we needed 480,000 Joules per kg
or 480 Joules/gram
by the way that is nothing like the usual accepted value.
To calculate the latent heat of vaporization of water, we can use the formula:
Q = mL
Where:
Q = Heat energy transferred
m = Mass of water
L = Latent heat of vaporization of water
In this case, the heat energy transferred can be calculated using the formula:
Q = P × t
Where:
P = Power of the heater (in watts)
t = Time taken (in seconds)
First, let's convert the power from watts to joules per second (J/s) by dividing by 1000:
P = 1000W / 1000 = 1 J/s
Next, let's convert the time taken from minutes to seconds:
t = 4 minutes × 60 seconds/minute = 240 seconds
Now we can calculate the heat energy transferred:
Q = 1 J/s × 240 seconds = 240 J
We know that the mass of water is 500g. Let's convert it to kilograms:
m = 500g / 1000 = 0.5 kg
Finally, we can substitute the values into the first equation to find the latent heat of vaporization:
240 J = 0.5 kg × L
Dividing both sides by 0.5 kg, we find:
L = 240 J / 0.5 kg = 480 J/kg
Therefore, the specific latent heat of vaporization of water is 480 J/kg.
To calculate the latent heat of vaporization of water, we can use the formula:
Latent heat = (Energy supplied by the heater) / (Mass of water vaporized)
First, let's calculate the energy supplied by the heater:
Energy supplied = Power × Time
The power of the heater is given as 1000 watts, and the time is given as 4 minutes. However, we need to convert the time to seconds to match the power unit:
Time = 4 minutes = 4 × 60 seconds = 240 seconds
Now we can calculate the energy supplied:
Energy supplied = 1000 watts × 240 seconds
Next, let's calculate the mass of water vaporized:
Mass = 500g
Finally, we can calculate the latent heat of vaporization:
Latent heat = Energy supplied / Mass of water vaporized
Plug in the values:
Latent heat = (1000 watts × 240 seconds) / 500g
Now, calculate the latent heat:
Latent heat = 240,000 watts-seconds / 500g
To simplify the units, 1 watt-second is equal to 1 joule, and 1 kilogram is equal to 1000 grams:
Latent heat = 240,000 joules / 0.5 kilograms
Simplify:
Latent heat = 480,000 joules per kilogram (or J/kg)
Therefore, the latent heat of vaporization of water is 480,000 J/kg.