find the stationary points of
y=x^4/4+4x^3/3-2x^2-16x+1?
stationary points are where y'=0
y' = x^3 + 4x^2 - 4x - 16 = (x+4)(x+2)(x-2)
so, what do you think?
y=x^4/4+4x^3/3-2x^2-16x+1?
y' = x^3 + 4x^2 - 4x - 16 = (x+4)(x+2)(x-2)
so, what do you think?