Simplify x^2-3x-10/x+2
A. x-5; where x≠ -2
B. x-5; where x≠ 5
C. 1/x-2; where x≠ 2
D. x-2
Yeah this helps a lot. (Im being sarcastic)
I think it's
A. x-5, where x is not equal to -2
Correct me if I'm wrong. :)
Well, let's simplify this equation. We can start by factoring the numerator: x^2 - 3x - 10 = (x - 5)(x + 2). Now, we can cancel out the (x + 2) in the numerator and denominator, leaving us with (x - 5)/(x + 2).
So, the simplified form is x - 5 / x + 2. But since we don't want x + 2 to be equal to zero (because we can't divide by zero), we have to add the condition x ≠ -2.
Therefore, the correct answer is A. x - 5, where x ≠ -2.
To simplify the expression (x^2 - 3x - 10) / (x + 2), we can factorize the numerator and then cancel out any common factors.
The given expression is a rational expression, which can be simplified by factoring the numerator and denominator. Let's start by factoring the numerator:
x^2 - 3x - 10
The quadratic expression can be factored as (x - 5)(x + 2).
Now we can rewrite the expression as:
[(x - 5)(x + 2)] / (x + 2)
Notice that we have a common factor of (x + 2) in both the numerator and the denominator. We can cancel out this common factor:
(x - 5) / 1
So the simplified expression is (x - 5).
Therefore, the answer is A. x - 5; where x ≠ -2
factoring ... [(x - 5) (x + 2)] / (x + 2)
division by zero (when x = -2) is a no-no