write the solubility product constant expression for the following
I) silver ethanediote
II) silver carbonate
III) lead
Iv)sulphate
v) boruim sulphate
I need the answer to this question
What is your trouble here?
Sure! To write the solubility product constant expressions, we need to consider the chemical equation for the dissolution of the substance in water and express the equilibrium expression based on the concentrations of the ions in solution.
I) Silver ethanedioate (silver oxalate)
The chemical equation of the dissolution of silver ethanedioate is:
Ag(C2O4) ⇌ Ag+ + (C2O4)2-
The solubility product constant expression for silver ethanedioate can be written as:
Ksp = [Ag+] * [(C2O4)2-]
II) Silver carbonate
The chemical equation for the dissolution of silver carbonate is:
Ag2CO3 ⇌ 2Ag+ + CO3^2-
The solubility product constant expression for silver carbonate can be written as:
Ksp = [Ag+]^2 * [CO3^2-]
III) Lead sulphate
The chemical equation for the dissolution of lead sulphate is:
PbSO4 ⇌ Pb2+ + SO4^2-
The solubility product constant expression for lead sulphate can be written as:
Ksp = [Pb2+] * [SO4^2-]
IV) Sulphate
It seems you may have made a typo in your question. If you meant to ask about the solubility product constant for sulphuric acid (H2SO4), it is not applicable since sulphuric acid is a strong acid and dissociates completely in water.
V) Barium sulphate
The chemical equation for the dissolution of barium sulphate is:
BaSO4 ⇌ Ba2+ + SO4^2-
The solubility product constant expression for barium sulphate can be written as:
Ksp = [Ba2+] * [SO4^2-]
Remember, these solubility product constant expressions represent the equilibrium concentrations of the ions in solution based on the chemical equation.