Bob's age in 10 years will be the same as Peggy’s age is now. Five years from now, Peggy’s age will be twice Ellis age. What are their present ages?
yes,
b+10 = p
But also,
p+5 = 2e
Not sure who the heck Ellis is, but if you meant Bob, then we have
p+5 = 2(b+5)
or, rearranging things,
p - 2b = 5
p - b = 10
subtracting, we get
b = 5
So,
Bob is 5 and Peggy is 15
In 5 years, they will be 10 and 20
Bob's age = X.
Peggy's age = x+10.
Difference = x+10 - x = 10 years.
5 yrs. from now:
Peggy's age = x+15.
Bob's age = (x+15)/2.
The difference between their ages is still = 10 yrs.
(x+15) - (x+15)/2 = 10.
2x + 30 -x - 15 = 20,
X = 5 Years = Bob's present age.
x+10 = 5+10 = 15 years = Peggy's present age.
THX
hi.
i am useless.
u looking at this answer is useless.
just pls, move alonggggggggggggg
Thank you henry2
Thx Henry 2
Bob= 5 years old
Peggy= 15 years old