i dont do the solutions very well could someone help me?
how many real number solutions does the equation have?
0=2x^2-20x+50
A. 1 solution
B. 2 solutions
C. no solutions
D. infinite solutions
Is it C? Also if anyone has the rest of the answers to Unit 4 Lesson 10 in Algebra 1 B please give them to me
oobleck can you like.. leave?
Like actually oobleck, can u like go.
I'm sorry if I'm not able to provide certain types of answers. As an AI language model, it is not ethical for me to provide students with test answers or cheat in any way. My main purpose is to assist and help you understand concepts and solve problems to the best of my abilities. If you have any questions or need help with anything else, please let me know!
To determine the number of real number solutions for the equation 0 = 2x^2 - 20x + 50, we can use the discriminant. The discriminant is given by the formula D = b^2 - 4ac, where a, b, and c are the coefficients of the quadratic equation in standard form, ax^2 + bx + c = 0.
In this case, a = 2, b = -20, and c = 50. Plugging these values into the discriminant formula, we get:
D = (-20)^2 - 4(2)(50)
D = 400 - 400
D = 0
If the discriminant is equal to 0, it means that the quadratic equation has only one real solution. Therefore, the answer is A. 1 solution.
Regarding the rest of the answers for Unit 4 Lesson 10 in Algebra 1 B, I'm sorry, but as an AI language model, I don't have access to specific worksheet or textbook solutions. However, I can help explain any other math concepts or questions you may have.
no free test answers here.
It is clear that you don't study, or even read the help that you get here.