P, Q and R are points in the same horizontal plan. The bearing Q from P is 160 degrees and bearing of R from 050 degrees. If /PQ/= 6m and /QR/= 4m, find the /PR/ and bearing of R from P, correct to the nearest degree

Draw the diagram.

Use the law of cosines to get PR
Now you have a triangle RPQ
Then you can use either the law of cosines or sines to get the angle at P. The bearing of R from P will be 160+that angle

PR = PQ + QR.

PR = 6m[160o] + 4m[50o],
X = 6*sin160 + 4*sin50 = 5.12 m.
Y = 6*Cos160 + 4*Cos50 = -3.07 m.
PR = 5.12 - 3.07i = 5.97m[-59o] = 5.97m[121o] CW.

To find the length of PR and bearing of R from P, we can use the Law of Cosines and basic trigonometry.

First, let's draw a diagram to visualize the given information:

```
P_________Q
/
/
/
/
R
```

Given information:
- PQ = 6m
- QR = 4m
- The bearing of Q from P is 160 degrees (measured clockwise from the reference direction, e.g., North).
- The bearing of R from the reference direction is 050 degrees (measured clockwise from the reference direction).

Now, let's start by finding the length of PR.

Using the Law of Cosines, we have:

PR^2 = PQ^2 + QR^2 - 2 * PQ * QR * cos(angle PQR)

To find the angle PQR, we can subtract the bearing of Q from P from 180 degrees (bearing angle subtends to 180 degrees):

angle PQR = 180 degrees - 160 degrees = 20 degrees

Substituting the values, we get:

PR^2 = 6^2 + 4^2 - 2 * 6 * 4 * cos(20 degrees)

PR^2 = 36 + 16 - 48 * cos(20 degrees)

PR^2 ≈ 36 + 16 - 48 * 0.9397 (cos(20 degrees) ≈ 0.9397)

PR^2 ≈ 52 - 45.1184

PR^2 ≈ 6.8816

PR ≈ √6.8816

PR ≈ 2.623 meters

Therefore, the length of PR is approximately 2.623 meters.

Next, let's find the bearing of R from P.

Since we know the bearing of R from the reference direction is 050 degrees, and the bearing of Q from P is 160 degrees, we can find the bearing of R from P by subtracting the bearing of Q from P from 050 degrees:

Bearing of R from P = 050 degrees - 160 degrees = -110 degrees

To convert -110 degrees to a positive bearing (measured clockwise from the reference direction), we can add 360 degrees:

Bearing of R from P = -110 degrees + 360 degrees = 250 degrees

Therefore, the bearing of R from P is approximately 250 degrees.

In conclusion, the length of PR is approximately 2.623 meters, and the bearing of R from P is approximately 250 degrees.