An electric force moves a charge of +1.80×10-4 C from point A to point B and performs +5.80×10-3 J of work on the charge. (a) What is the change in the electrical potential energy of the charge as it moves from A to B? (b) Determine the potential difference between the two points.
work= given
a) change in PE=work it took to get there.
b) change in potential = work to get there divided by the charge.
To find the answers to these questions, we need to use the following formulas:
(a) The change in electrical potential energy (ΔPE) is given by the equation:
ΔPE = W
where ΔPE is the change in electrical potential energy, and W is the work done on the charge.
(b) The potential difference (V) between two points is given by the equation:
V = ΔPE / q
where V is the potential difference, ΔPE is the change in electrical potential energy, and q is the charge.
Let's calculate the answers step by step:
(a) What is the change in the electrical potential energy of the charge as it moves from A to B?
The given information is:
Charge, q = +1.80×10-4 C
Work done on the charge, W = +5.80×10-3 J
Using the formula ΔPE = W, we can substitute the values:
ΔPE = +5.80×10-3 J
So, the change in electrical potential energy of the charge as it moves from A to B is +5.80×10-3 J.
(b) Determine the potential difference between the two points.
Using the formula V = ΔPE / q, we can substitute the values:
V = (+5.80×10-3 J) / (+1.80×10-4 C)
Now, let's perform the calculation:
V = 32.2 V (rounded to two decimal places)
Therefore, the potential difference between the two points is 32.2 volts.