Write the following equation in logarithmic form
a^(4b-6)=3c+d
(4b-6) log a = log(3c+d)
or
4 b log a - 6 log a = log(3c+d)
or
log (4 b/6) = log(3c+d)
or
log (2b/3) = log(3c+d)
To write the equation a^(4b-6) = 3c + d in logarithmic form, we need to understand the properties of logarithms.
In logarithmic form, we express an equation of the form x = b^y as log base b of x = y.
Applying this property to our equation, we can rewrite it as:
log base a of (a^(4b-6)) = log base a of (3c + d)
Since a is the base of the logarithm, the base for our logarithm is a. The argument of the logarithm is a^(4b-6).
So, the equation in logarithmic form is:
log base a of (a^(4b-6)) = log base a of (3c + d)