If a car goes from 0 to 75 mph in 7 seconds with constant acceleration, what is that acceleration?
clearly, the acceleration is (75mi/hr)/7s
Those are not conventional units, so maybe you want just ft/s^2.
now, 60 mi/hr = 88 ft/s, so that makes it
(88 * 75/60)/7 ft/s^2
To find the acceleration of the car, you can use the formula:
acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 0 mph
Final velocity (v) = 75 mph
Time (t) = 7 seconds
Plugging the values into the formula:
acceleration = (75 mph - 0 mph) / 7 seconds
Simplifying:
acceleration = 75 mph / 7 seconds
So, the acceleration of the car is approximately 10.71 mph/second.
To find the acceleration, we can use the kinematic equation:
v = u + at
Where:
v = final velocity (75 mph)
u = initial velocity (0 mph)
a = acceleration (unknown)
t = time taken (7 seconds)
Rearranging the equation to solve for acceleration (a), we have:
a = (v - u) / t
Substituting the given values, we get:
a = (75 mph - 0 mph) / 7 s
To find the acceleration in SI units (m/s²), we need to convert the velocity from mph to m/s. The conversion factor is 0.44704 m/s per 1 mph.
So, the equation becomes:
a = (75 mph * 0.44704 m/s) / 7 s
Evaluating this expression, we can find the acceleration.