A man using 80kg garden tractor on a level surface exert a force of 50N at 65^0 to the ground. Find the vertical force of the garden tractor on the ground
if the force is 65 deg measured from the vertical to ground, then
Fnormal=80*9.8N*cos65deg
To find the vertical force exerted by the garden tractor on the ground, we first need to resolve the given force of 50N into its vertical and horizontal components.
The vertical component can be found using trigonometry, specifically the sine function. Since the angle between the force and the ground is given as 65 degrees, the vertical component (Fv) can be calculated as:
Fv = F * sin(θ)
Where F is the magnitude of the force (50N) and θ is the angle (65 degrees).
Substituting the values, we can calculate Fv:
Fv = 50N * sin(65°)
Using a scientific calculator, we find that sin(65°) ≈ 0.9063.
Therefore,
Fv ≈ 50N * 0.9063
Fv ≈ 45.315N
So, the vertical force exerted by the garden tractor on the ground is approximately 45.315N.