can someone plz help me with this?
What mass of sucrose (C12H22O11) must be dissolved to make 460 mL of a 1.10M solution?
thanks
concentration= molessolute/volume
moles solute=conc*volume
massSolute/molmassSolute=conc*volume
masssolute=conc*volume*molmassSolute
volume is in liters, mass in grams, molmass in grams, concentration in Molarity.
are you telling me I have to find this one?:masssolute=conc*volume*molmassSolute
I got an answer of 173.2g doing it another way. Is that right?
nevermind, i found the answers in the back of the book and i'm right
Yes, you are correct in finding the mass of the solute using the formula: massSolute = conc * volume * molmassSolute.
To find the mass of sucrose that must be dissolved, we need to use the given values: concentration (1.10 M) and volume (460 mL).
First, convert the volume from milliliters to liters: 460 mL = 0.460 L.
Next, we need to know the molar mass of sucrose (C12H22O11). Adding up the atomic masses, we get:
12 (C) + 22 (H) + 11 (O) = 342 g/mol.
Using the formula:
massSolute = conc * volume * molmassSolute
massSolute = 1.10 M * 0.460 L * 342 g/mol
massSolute = 173.22 g
Therefore, the mass of sucrose that must be dissolved to make a 1.10 M solution with a volume of 460 mL is approximately 173.22 grams.
It's great to hear that you found the correct answer using a different method. If you have any further questions, feel free to ask!