When the brake are applied to a moving car travelling 60km\hr it decelerate at uniform rate of 5m\s
And your question?
how much time does it take to stop?
vf=vi+1/2 a t^2
0=vi-4.9 t^2 change vi to m/s, solve for t
how far does it go?
Vf^2=Vi^2 +2ad
solve for distance d. Again,change speed to m/s
To find the time it takes for the car to come to a stop, we can use the equations of motion.
The first equation of motion is:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given that the car is decelerating at a uniform rate, the acceleration is negative (-5 m/s^2) because it is acting opposite to the direction of motion. The initial velocity of the car is 60 km/hr, which needs to be converted to m/s:
60 km/hr * (1000 m/1 km) * (1 hr/3600 s) = 16.67 m/s
Substituting the values into the equation:
0 (final velocity) = 16.67 m/s (initial velocity) + (-5 m/s^2) * t
Simplifying the equation, we get:
0 = 16.67 - 5t
Rearranging the equation to solve for time:
5t = 16.67
t = 16.67 / 5
t = 3.34 seconds
Therefore, it will take approximately 3.34 seconds for the car to come to a stop when the brakes are applied.