2c-d=-2
d=-4c+20
add the two equations.
2c=-2-4c+20
add 4c to each side
To find the solution to this system of equations, you can use the method of substitution. It involves solving one equation for a variable and then substituting that expression into the other equation.
Let's start with the second equation, d = -4c + 20. We can solve this equation for d by isolating it on one side:
d = -4c + 20
Now we can substitute this expression for d in the first equation, 2c - d = -2:
2c - (-4c + 20) = -2
Simplifying the equation:
2c + 4c - 20 = -2
Combining like terms:
6c - 20 = -2
Next, we can isolate c by adding 20 to both sides:
6c = 18
Finally, we divide both sides by 6 to solve for c:
c = 3
Now that we have the value of c, we can substitute it back into one of the original equations to find the value of d. Let's use the second equation:
d = -4c + 20
d = -4(3) + 20
d = -12 + 20
d = 8
Therefore, the solution to the system of equations is c = 3 and d = 8.