A body is executing of amplitude 1m . Its velocity while passing through mean position is 10m/s . Find its frequency
x = 1 sin (2 pi f t)
v = 2 pi f cos(2 pi f t)
so
2 pi f = 10
To find the frequency of a body executing simple harmonic motion, we can use the formula:
frequency (f) = velocity (v) / (2 * amplitude (A))
Given that the amplitude (A) is 1m and the velocity (v) while passing through the mean position is 10m/s, we can substitute these values into the formula to calculate the frequency:
f = 10m/s / (2 * 1m)
Simplifying further:
f = 10m/s / 2
f = 5 Hz
Therefore, the frequency of the body is 5 Hz.