The population of Andhra Pradesh was 5.4 * 10^7 in 1988. If the population was growing at a constant rate of 2.4% per annum, what was the population in 2008 A.D ( Given that (1.024)^20 = 1.60694)
just multiply your 1988 population by 1.60694
why do you think they gave you that number?
No
Question ka answers
To find the population of Andhra Pradesh in 2008, we need to use the formula for compound interest:
P = P_0 * (1 + r)^n
Where:
P is the final population
P_0 is the initial population
r is the growth rate per period
n is the number of periods
Given:
P_0 = 5.4 * 10^7 (population in 1988)
r = 0.024 (2.4% growth rate per annum)
n = 2008 - 1988 = 20 (number of years)
Substituting these values into the formula:
P = (5.4 * 10^7) * (1 + 0.024)^20
Now, let's plug it into a calculator or solve it step by step:
1 + 0.024 = 1.024
So, the equation becomes:
P = (5.4 * 10^7) * (1.024)^20
Using the given value of (1.024)^20 = 1.60694:
P = (5.4 * 10^7) * 1.60694
Calculating further:
P = 8.71 * 10^7
Therefore, the population of Andhra Pradesh in 2008 was approximately 8.71 * 10^7.