Can someone please solve these for me?
Thank you.
x^2 + 5x + 6 = 0
[SQRT(x + 3)] = 2[SQRT(x)]
first one is (x+2)(x+3)
if you use FOIL method
Thank you ..
If i had to solve for x what would be my answer if I had to choose from..
Ano solution
B{-2,-3}
C{2,3}
D-2
E3
F0
3(4x + 6) + 7x
Thank you What would be the answer C?
From (x+3)(x+2) = 0
Set each factor to zero and solve; e.g.,
x+3 = 0
x = -3
and
x+2=0
x=-2
so the solution to the problem is x =-3; -2.
Ok thank you for your help.
Can you help me solve this equation?
9y2 + 16=0
Certainly! I can help you solve these equations step by step.
1. x^2 + 5x + 6 = 0:
To solve a quadratic equation like this one, you can use the quadratic formula. The quadratic formula is:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 1, b = 5, and c = 6.
Substituting these values into the quadratic formula, we get:
x = (-5 ± √(5^2 - 4*1*6)) / (2*1)
Simplifying further:
x = (-5 ± √(25 - 24)) / 2
x = (-5 ± √1) / 2
This simplifies to:
x = (-5 ± 1) / 2
So, there are two solutions:
x = (-5 + 1) / 2 = -4 / 2 = -2
x = (-5 - 1) / 2 = -6 / 2 = -3
Therefore, the solutions to the equation x^2 + 5x + 6 = 0 are x = -2 and x = -3.
2. [SQRT(x + 3)] = 2[SQRT(x)]:
To solve this equation, we can square both sides of the equation to eliminate the square root symbols.
Taking the square of [SQRT(x + 3)], we get:
[SQRT(x + 3)]^2 = (2[SQRT(x)])^2
x + 3 = 4x
Rearranging the equation:
4x - x = 3
3x = 3
Simplifying further:
x = 3 / 3
x = 1
Therefore, the solution to the equation [SQRT(x + 3)] = 2[SQRT(x)] is x = 1.
I hope this helps! Let me know if you have any further questions.