The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground?
Given: g = -9.8 meters/second2
To find out how long it would take an apple falling from a height of 4.00 meters to reach the ground, we can use a basic physics formula known as the kinematic equation:
h = (1/2) * g * t^2
Where:
h = Height of the apple tree (4.00 meters)
g = Acceleration due to gravity (-9.8 meters/second^2)
t = Time taken to reach the ground (what we want to find)
To solve for t, we need to rearrange the equation:
t^2 = (2h) / g
Let's substitute the given values and solve for t:
t^2 = (2 * 4.00 meters) / (-9.8 meters/second^2)
t^2 = -0.8163
Since time cannot be negative, we discard the negative value and take the positive square root:
t = √(-0.8163)
t = 0.904 seconds
Therefore, it would take approximately 0.904 seconds for an apple falling from a height of 4.00 meters to reach the ground.
h=1/2 g t^2
t= sqrt(2h/g)=sqrt(2*4/9.8) close to one second, work that out.