what is the prime factorization for 40
http://www.2dtx.com/prime/prime40.html
To find the prime factorization of 40, follow these steps:
Step 1: Start by dividing 40 by the smallest prime number, which is 2.
Quotient: 40 ÷ 2 = 20
Step 2: Continue dividing the quotient by 2 until you can no longer divide evenly.
Quotient: 20 ÷ 2 = 10
Quotient: 10 ÷ 2 = 5
Step 3: 5 is a prime number, so it cannot be divided further.
Therefore, the prime factorization of 40 is:
40 = 2 × 2 × 2 × 5
or, in exponent notation:
40 = 2^3 × 5
To find the prime factorization of 40, you need to find the prime numbers that divide evenly into 40. Here's how you can do it:
Step 1: Start by dividing 40 by the smallest prime number, which is 2. Since 40 is divisible by 2, divide 40 by 2 to get 20.
Step 2: Next, divide 20 by 2 again to get 10.
Step 3: Divide 10 by 2 once more to get 5. Now, 5 is a prime number and it cannot be divided further.
Step 4: Write down all the divisors you used: 2, 2, and 5.
Step 5: To get the prime factorization, multiply all the divisors together: 2 x 2 x 5 = 20.
Therefore, the prime factorization of 40 is 2 x 2 x 5, which can also be written as 2^3 x 5.