Table salt has a solubility of 36g of salt in 100g of water at 40 degrees celcius. If 15g of salt is added to 50g of water at the same room temperature, is the resulting solution saturated of unsaterated? Explain your answer.
The solubility is 36 g/100. So what's the solubility in 50 g? That's 36 g salt x (50/100) = 18 g. You have 15 g to put in the 50 g H2O. So will that be saturated or not?
To determine whether the resulting solution is saturated or unsaturated, we need to compare the amount of salt dissolved in the solution with the maximum amount of salt that can be dissolved at that temperature.
The solubility of table salt in water at 40 degrees Celsius is given as 36g of salt in 100g of water. This means that 100g of water can dissolve a maximum of 36g of salt at that temperature.
In this case, 50g of water is used, and 15g of salt is added to it. So, our goal is to compare the amount of salt dissolved (15g) with the maximum amount of salt that can be dissolved (36g) in 50g of water.
To do this, we can use a simple ratio:
15g (amount of salt added) / 36g (maximum solubility) = x (amount dissolved) / 50g (amount of water used)
Cross-multiplying, we get:
15g * 50g = 36g * x
750g = 36g * x
x ≈ 20.8g
The resulting solution has approximately 20.8g of salt dissolved. Since this is less than the maximum solubility of 36g for 50g of water at 40 degrees Celsius, the solution is unsaturated. It means that there is still room for more salt to be dissolved in the solution at the given temperature.