A fair charged $2.50 admission for adults and a dollar for children. The receipts for 1 day were $1951 on 1300 paid admissions. How many adults attended the fair that day?
2.50a + 1.00(1300-a) = 1951
a = 434
434
Yah it is correct
Yup! This is correct!
You could also do :
x + y = 1300
x-2.5 +y = 1951
Subtract
1.5x = 651
x = 434
Yeah it is because the equation would be:
2.5x+1*(1300-x)=1951 When you solve it and substitute the variables, you should get 434
nice
1
according to my calculations the answer is 100% 434 🤓
To find the number of adults who attended the fair that day, we can set up a system of equations.
Let's assume the number of adults who attended the fair is "A" and the number of children is "C."
From the information given, we know that the admission for adults is $2.50 and the admission for children is $1. We also know that the total number of paid admissions was 1300, so we can set up the equation:
A + C = 1300 (equation 1)
Additionally, we are given the total receipts for the day, which is $1951. Since the admission for adults is $2.50 and the admission for children is $1, we can set up another equation to represent the total receipts:
2.50A + 1C = 1951 (equation 2)
To solve this system of equations, we can use a method called substitution. Let's solve equation 1 for C:
C = 1300 - A (equation 1a)
Now, substitute equation 1a into equation 2:
2.50A + 1(1300 - A) = 1951
Simplifying the equation:
2.50A + 1300 - A = 1951
Combine like terms:
1.50A + 1300 = 1951
Subtract 1300 from both sides:
1.50A = 1951 - 1300
1.50A = 651
Divide both sides by 1.50 to isolate A:
A = 651 / 1.50
A = 434
Therefore, there were 434 adults who attended the fair that day.