The probability that a randomly selected two-year-old male stinkbug will live to be three years old is .59963 what is the probability that to randomly selected two-year-old male stinkbugs will live to be three years old? What is the probability that for randomly selected two-year-old male stink bugs live to be three years old ?
.59963
To find the probability that two randomly selected two-year-old male stinkbugs will live to be three years old, you can multiply the individual probabilities together.
Given that the probability of a single randomly selected two-year-old male stinkbug living to be three years old is 0.59963, you can calculate the probability for two randomly selected stinkbugs using the following formula:
P(both bugs live) = P(bug 1 lives) * P(bug 2 lives)
Substituting the given probability into the formula, we have:
P(both bugs live) = 0.59963 * 0.59963
Calculating this expression, you will find that the probability that two randomly selected two-year-old male stinkbugs will live to be three years old is approximately 0.35955 or 35.955%.
Note that we squared the probability since we are dealing with two independent events (the probability of the first bug living and the probability of the second bug living).